Question

express in partial fractions:
(2x^4 -3x^3+4x-2)/(x^2-x+1)²(x-1)

Answer 1

\[\frac{ (2x^4 -3x^3+4x-2) }{ (x^2-x+1)² (x-1)}\]

Answer 2

or

Answer 3

\[\frac{ (2x^4 -3x^3+4x-2) }{ (x^2-x+1)² }(x-1)\]

Answer 4

what's your Question ?

Answer 5

\[\frac{2x^4-3x^3+4x-2}{(x^2-x+1)^2(x-1)}=\frac{Ax+B}{x^2-x+1}+\frac{Cx+D}{(x^2-x+1)^2}+\frac{E}{x-1}\]