Question

Giving Medal!


Solve 4m - 2n^2 = 2m - 72 for m
a.
m = -72
c.
m = 72
b.
m = 2n^2 - 36
d.
m = n^2 - 36

Answer 1

4m - 2n^2 = 2m - 72
4m - 2m = 2n^2 - 72
m = ?

Answer 2

well since you didn't put which one you're solving for, I'll put for both:

4m-2n^2=2m-72
subtract both sides by 2m
2m-2n^2= -72
add both sides by 2n^2
2m= 2n^2 -72
divide both sides by 2
m = n^2 - 36

That's for m

For n:

4m-2n^2 = 2m - 72
subtract both sides by 4m
-2n^2 = -2m -72
multiply both sides by -1
2n^2 = 2m- 72
divide both sides by 2
n^2 = m - 36
take the square root of both sides
n = sqrt(m - 36)
if m and 36 were being multiplied by each other you can put 6sqrt of m, but since it's addition/subtraction, you can't, it's one term underneath the square root sign