Students in an English class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. The average score S(t), in percent, after t months was found to be given by S(t) = 68 − 20 log (t + 1), t ≥ 0. What was the average score after 14 months?

Question

Students in an English class took a final exam. They took equivalent forms of the  exam at monthly intervals thereafter. The average score S(t), in percent, after t months  was found to be given by S(t) = 68 − 20 log (t + 1), t ≥ 0. What was the average score after 14 months?

anonymous · Answer

t = 14.

Sub in t = 14 into S(t) = 68 − 20 log (t + 1),

S(t) = 68 − 20 log (14 + 1) =
S(t) = 68 − 20 log (15)
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