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In circle A shown below, Segment BD is a diameter and the measure of Arc CB is 54°.
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What is the measure of ∡DBC? 54° 36° 27° 63
find Arc CD
∡DBC = Arc CD / 2
@ganeshie8 how do I find it
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CD Arc
CD Arc + CB Arc = 180 CD Arc + 54 = 180 CD Arc = ?
126
Yes ! take half of that, cuz inscribed angle = half of central angle
<DBC = CD/2 = 126/2 = ?
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63
correct
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