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4/y+3= 3/y+4
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i need to know y
is the problem writen as 4/(y+3)= 3/(y+4)?
there proportions
like fractions
\[\frac{ 4 }{ y+3 }=\frac{ 3 }{y+4 }\] 4(y+4)=3(y+3) 4y+16=3y+9 4y-3y=9-16 y=-7
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\[\frac{4}{y+3}=\frac{3}{y+4} \rightarrow 4(y+4)= 3(y+3)\] i.e. 4y+16= 3y+9 i.e. 4y-3y= 9-16 i.e. y= -7
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