Question

is s^6+64 factored to be (s^2)(s^4-4s^4+16)

Answer 1

first, setting s^6+64 as (s^2)^3+4^3

Answer 2

then use the formula :
a^3 + b^3 = (a+b)(a^2 - ab + b^2)

Answer 3

okay

Answer 4

in this case just change a = s^2 and b = 4
now distribute them into formula above

Answer 5

did you get it ?