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4^x=12
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I just don't understand the log problems at alllllll :(
4^x=12 Taking Log both sides log4^x=log12 xlog4=log12 x(0.60)=1.07 x=1.07/0.60 x=1.8
I didn't log both sides -____- wow.. that's embarrassing haha. Thank you so much! with the final I just divide 1.07 by 0.60? Thank you :)
Anytime.
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