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If (x + 5) - 2(4x - 1) = 0, what is the value of x? i got a decimal. how do i solve this?
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you have x + 5 -8x + 2 = 0
(x + 5) - 2(4x - 1) = 0 Distribute the -2 to the right side. (x + 5) - 8x + 1 = 0 Remove() x + 5 - 8x + 1 = 0 Add and Subtract.
how do i remove the 0? @some_someone
(x + 5) - 2(4x - 1) = 0 Distribute the -2 to the right side. (x + 5) - 8x + 1 = 0 Remove() x + 5 - 8x + 1 = 0 Add and Subtract. x - 8x = ___ 5 + 1 = ___
I never said 0 @GABY11 I said remove() As in () <=== parenthesis
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wait how did you get positive 1? isnt it suppose to be positive 2? @some_someone
yes it is +2
-7x +7 = 0 -7x = -7 x = 1
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