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factor completely 8x^4-20x^3-12x^2
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Looks like \(4x^{2}\) is a factor.
Would this be prime?
No. What's wrong with the factor I just gave you? What does it leave after factoring that out?
so the answer is 4x^2(2x^2-5x-3)?
It would be the answer if that trinomial cannot be factored. Can it?
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no
Let's see... \((-5)^{2} - 4(2)(-3) = 25 + 24 = 49 = 7^{12}\) Whoops. It CAN be factored. Try harder. 2x^2-5x-3 (2x __ ____)(x __ ____) Fill in the blanks.
i dont know
You've never factored anything?
i have
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Good, then. There are only four possibilities. Try them out and see which one works. (2x + 1)(x - 3) (2x - 1)(x + 3) (2x + 3)(x - 1) (2x - 3)(x + 1) Which?
the first i get it now thanks
There you go.
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