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Mathematics 22 Online
OpenStudy (anonymous):

cos x +1=sinx....solve the equation

OpenStudy (anonymous):

Try squaring both sides. Note than sinx^2 + cosx^2 = 1

OpenStudy (anonymous):

try using additon formula with cosx+1-sinx=0

OpenStudy (anonymous):

cosx +1 =sinx cosx-sinx=1 Squaring both sides gives, cos^2x - 2cosx sinx +sin^2x=1 1-2cosxsinx=0 2sinx cosx = 0 sinx cosx =0 Either sinx =0 OR cosx=0 Now, solve these and find all the values of x in the range you need... also check for all the values of x whether they are constient with the given equation or not as we have squared which would give incorrect solutions also.

OpenStudy (anonymous):

it should be cosx-sinx=-1

OpenStudy (anonymous):

oh yess...... but that makes no difference

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

i would have done it a different way

OpenStudy (anonymous):

but much easier

OpenStudy (anonymous):

you can post it

OpenStudy (anonymous):

i mean urs is much easier

OpenStudy (anonymous):

Did u convert sinx-cosx into Rsin(x+A) I mean this method ???

OpenStudy (anonymous):

yea not sin , cos

OpenStudy (anonymous):

ohh i see .. thanks guys

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