HELP ME!!!!!!

What is the length of the conjugate axis?

((y-2)^2/16)-((x+1)^2/144)=1

Question

HELP ME!!!!!!

What is the length of the conjugate axis?

((y-2)^2/16)-((x+1)^2/144)=1

tkhunny · Answer

24 - Eyeball problem.  Don't let this kind get away from you.

anonymous · Answer

how did you get that?

tkhunny · Answer

There's a positive and a negative piece in this form.
The positive piece (y in this case), listed first, defines the transverse axis in it's denominator.

16 = 4^2 and then 2*4 = 8 -- This is the length of the transverse axis
Also, usually stated simply as a = 4

The negative piece (x in this case), listed second, defines the conjugate axis in it's denominator.

144 = 12^2 and then 2*12 = 24 -- This is the length of the conjugate axis
Also, usually stated simply as b = 12

anonymous · Answer

ok i got it now thank you