How do you find the slope of the curve, the line that is tangent to the curve, or the line that is normal to the curve, at the given point, as requested?
y6 + x3 = y2 + 12x, slope at (0, 1)

Question

How do you find the slope of the curve, the line that is tangent to the curve, or the line that is normal to the curve, at the given point, as requested?
y6 + x3 = y2 + 12x, slope at (0, 1)

anonymous · Answer

Differentiate the above equation, i believe you'll need implicit differentiation.

Finding dy/dx, substitute the x value into dy/dx to find the gradient at that point

wesdg1978 · Answer

For dy/dx, I get:|dw:1373518052764:dw|