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given f(x)=sqrt{6x} and g(x)=1/x-6 . which value is in the domain 8 4 2 6 ?
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\[6x \ge 0\] and \[x-6\neq 0\] so \[x \ge 0\] and \[x \neq 6\] so \[D: x \in <0;6) \cup (6: \infty)\]
is that what you mean?
it was wrong *tear*
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