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OpenStudy (anonymous):
2(6-x)=x(x+5)
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OpenStudy (anonymous):
Expanding: 12 - 2x = x^2 + 5x x^2 + 7x - 12 = 0 solve for x.
OpenStudy (anonymous):
Yes solve for x and its in the quadractic formula
OpenStudy (primeralph):
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OpenStudy (anonymous):
Yes lol
OpenStudy (anonymous):
x^2 + 7x - 12 = 0 x^2 + 7x - 12 + (3.5)^2 = (3.5)^2 (x+3.5)^2 = (3.5)^2 + 12 (x+3.5) = + (3.5)^2 + 12 OR (x+3.5) = -(3.5)^2 -12 solve for X
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