Question

A standard number cube is tossed. Find P(even or greater than 4).

Answer 1

Desired outcomes: 2,4,5,6
All outcomes: 1,2,3,4,5,6
# of desired outcomes: 4
Total # of possible outcomes: 6\[P = \frac{\textrm{# of desired outcomes}}{\textrm{total # of outcomes}} = \frac{4}{6} = \frac{2}{3}\]

Answer 2

thanks