OpenStudy (anonymous):

simplify 3/4i an imaginary number cannot be in the denominator

4 years ago
OpenStudy (anonymous):

what grade is this

4 years ago
OpenStudy (anonymous):

algebra II

4 years ago
OpenStudy (anonymous):

Multiply the top and bottom by "i" That is the factor i/i.

4 years ago
OpenStudy (anonymous):

wouldnt it be a negative i?

4 years ago
OpenStudy (anonymous):

Why do you think you would need negative "i" ?

4 years ago
OpenStudy (anonymous):

because wouldnt you use the discriminant to remove the i?

4 years ago
OpenStudy (anonymous):

There is no discriminant here, at least in the problem as stated. Just try to do that multiplication of top and bottom and see what you get. btw, the support for utilizing the technique I suggested is that any number, complex or not, over the same number is the factor "1" and that is the multiplicative identity so you can legitimately perform that operation.

4 years ago
OpenStudy (anonymous):

okay ill give it a try to that would give me 3i/-1

4 years ago
OpenStudy (anonymous):

oh wait that would get 3i/-4

4 years ago
OpenStudy (anonymous):

\[\frac{ 3 }{ 4i } \times \frac{ i }{ i } = \frac{ 3i }{ 4(i ^{2}) } = \frac{ 3i }{ (4)(-1) } = \frac{ -3i }{ 4 }\]

4 years ago
OpenStudy (anonymous):

Yes, you got it! Good job!

4 years ago
OpenStudy (anonymous):

okay its making it clear now thanks for the help!!

4 years ago
OpenStudy (anonymous):

uw! Good luck to you in all of your studies and thx for the recognition! @TheAnon16

4 years ago
OpenStudy (anonymous):

no thank you for the help ive been stuck on this for a day or two now

4 years ago
OpenStudy (anonymous):

I'm sorry tat was the case. Just make it over to Openstudy more quickly to save yourself some unnecessary frustration.

4 years ago
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