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Algebra
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focus, vertex, and directrix for 16(x-9)=(y+9)^2
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well this is in the form (y - k)^2 = 4a(x - h) its a parabola that is open to the right with the line of symmetry parallel to the x axis here is an example |dw:1373574339774:dw| so the vertex is at (h, k) so 4a = 16 a is the focal length... so find a the focus will be (h + a, k) the directrix is x = h - a hope this helps
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