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Match the inequality with the solution. Match Term Definition 3z + 6(z + 1) < -3 A) z < -1 4z – z + 2 > 5 B) z > -1 6( z + 1) < 12 C) z > 1 -5z + 8 < 10 – 3z D) z < 1
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let start by solving the easy one 4z -z +2 > 5 do you know how to solve
No.
ok, first you can add the variables as follows 4z-z = 3z 3z +2 >5
now subtract 2 on both sides you have 3z >3, now divide by 3 and what do you get ?
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Idk .-. Ima gone and guest.
what is 3/3
1
good then z>1
We got 3 more .-.
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