check √(2x+5) for extraneous solutions and show your work.
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OpenStudy (anonymous):
is that the full question?
OpenStudy (anonymous):
sorry the question is:check √(2x+5)=x+3 for extraneous solutions and show your work.
OpenStudy (anonymous):
okay i was about to say...
OpenStudy (anonymous):
lol I know
OpenStudy (anonymous):
well just solve for x, there should be 2 values
then test your values for x and see if they both actually work
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OpenStudy (anonymous):
when I solved for x I got (x+2)(x+2)
OpenStudy (anonymous):
which is basically just -2 rite?
OpenStudy (anonymous):
so....
OpenStudy (anonymous):
start by squaring everything to get rid of the radical
2x+5 = (x+3)^2
2x+5 = x^2 +6x +9
0 = x^2 +4x +4
(x+2)(x+2)
x=-2
now lets test it
√(2x+5)=x+3
√(-4+5)=-2+3
1 = 1
works
no extraneous solutions
OpenStudy (anonymous):
ok that's what I had! but since I didn't find any I just wanted a 2nd opinion
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OpenStudy (anonymous):
thank u! :)
OpenStudy (anonymous):
well it says just to check for them haha
you're welcome