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Can someone help me with this?? I'm getting confused with the i's. Write a polynomial of the smallest degree with roots 6, 3i and -3i.
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use sum and product for the conjugate roots
then you will get a quadratic facotr and a linear factor
Is this the right direction - (x-6) (x-3i) (x-(-3i)
sum 3i-3i=0 product 3ix-3i=9 quadratic factor = x^2-Sx+P x^2-0x+9 x^2+9 is ur quadratic factor
(x-6)(x^2+9)
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then expand
Thanks! I think I got it: x^3-6x^2+3x-54=0
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