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OpenStudy (anonymous):
Reflecting over which line will map the trapezoid onto itself? (picture coming in a few short moments!)
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OpenStudy (anonymous):
Directrix (directrix):
The trapezoid is isosceles so the reflection line will have to be, I think, the perpendicular bisectors of those two sides. Look at the attachment. Does the line appear to be x = -1 ?
Directrix (directrix):
@catsarecool1995
OpenStudy (anonymous):
Yes!! and that is one of the options that they gave me. Thanks!!!
Directrix (directrix):
You're welcome, CoolCat.
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OpenStudy (anonymous):
Woah. I'm so excited that I got called a cool cat. Thank you. WOOP!
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