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plug your function g(x) into the "x" for f(x). \[\large f(x)= 2x-1\]\[\large g(x) = x+2\]\[\large f(g(x))= 2(x+2) - 1\] Solve :)
Understand?
Yeah I got it, I fix the complete opposite I did was like f(g)+x. Retarded? AMIRITE.
Anyway it's 2x+1 :)
ocrap is it 2x-1?!
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in a party, each member invited takes a number to be served. if the first member took the number 32 and he last member took number 520. How many members were there that day?
f(g(x)) = 2x +2 -1 = ?
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