Question

How do you start this equation? Use the half-angle identities to find all solutions on the interval [0,2pi) for the equation sin^2x=cos^2x/2

Answer 1

Thanks!

Answer 2

\[x=\pi\]
\[x=\frac{ \pi }{ 3 }\]
\[x=\frac{ -\pi }{ 3 }\]