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(x+2)(2x+3)=6 My options: (-2, -3/4) (-7/2,0) (0)
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First Expand the lhs to get \[2 x^2+7 x+6=6 \]
Second Step \[2 x^2+7 x=0 \]
Third Step \[ x( 2 x +7)=0 \]
Can you finish it?
Wait, how did they get in the parentises?
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You factor the x out
Im trying to figure it out and I'm going backwards.
OK. Take your time
Wouldn't be (-7/2,0) because you can't factor a 7?
@eliassaab
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Yes x=0 x=-7/2
Ha! Lol thank you!
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