Question

Solve:
(x^2-1)(x^2+3x+2)=0

A)x=-1; x=1; x=2
B)x=-1; x=1; x=-2
C)x=-1; x=0; x=2
D)x=1; x=0; x=2

Answer 1

factor both polynomials

(x^2-1) = (x+1)(x-1)

(x^2+3x+2) = (x+2)(x+1)

so we get

(x+1)(x-1)(x+2)(x+1) = 0

Answer 2

so that means x = -2, -1, and 1

Answer 3

@robz8 is correct

Answer 4

thank you for also showing how you did it, i struggle with these.