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What are the solutions of 2x2 + 8x = -26 A) -2 ± 3 i B) -2 ± i C) 2 ± 6 i D) -3 ± 2 i
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Write the equation as \[ 2 x^2 +8 x +26 =0 \] and compute \[ b^2-4ac \]
You can simplify it by dividing by 2 to get \[ x^2 + 4x +13=0 \]
so 8^2-4(2)(-46)?
@eliassaab
im so confused
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Use the simplified version \[ x^2 + 4x +13=0\\ a=1; b =4; c=13 \]
\[ b^2 - 4 a c = 4^2 - 4(1)13=16- 52=-36 \]
\[ \frac {- 4 \pm i \sqrt {36}}{2}= -2 \pm 3i \]
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So it is A
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