Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

sum of series (1/1*2)+(1/2*3)+(1/3*4)+....(1/n*(n+1)

OpenStudy (shubhamsrg):

you have to find summation (1/n(n+1) ) note that 1/n(n+1) = [ (n+1) - n ]/[ n(n+1) ] does this help your case?

OpenStudy (anonymous):

Does we solve it for n terms first??

OpenStudy (shubhamsrg):

just simplify [ (n+1) - n ]/[ n(n+1) ] first.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!