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OpenStudy (anonymous):
sum of series (1/1*2)+(1/2*3)+(1/3*4)+....(1/n*(n+1)
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OpenStudy (shubhamsrg):
you have to find summation (1/n(n+1) ) note that 1/n(n+1) = [ (n+1) - n ]/[ n(n+1) ] does this help your case?
OpenStudy (anonymous):
Does we solve it for n terms first??
OpenStudy (shubhamsrg):
just simplify [ (n+1) - n ]/[ n(n+1) ] first.
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