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The equation of the straight line joining the points of intersections of x^2 + y^2 = 12 and y^2 = 4x is given by?
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1. x = -2 2. x = 2 3. y = -2 4. y = 2
x^2 + y^2 = 12 ; replace y^2 with 4x x^2 + 4x = 12 and solve the quadratic
most likely one solution will be extranuous, so test them out to be sure
I got two solutions: x = -6 and x = 2. What now?
y^2 = 4x is y^2 ever negative?
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and ... which one fits the options?
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