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Mathematics 17 Online
OpenStudy (anonymous):

simplify completely 4x3+5x2+3x -------------- x

OpenStudy (ivettef365):

just take out one x from each of the top

OpenStudy (ivettef365):

so you get 4x^2 +5x +3

OpenStudy (anonymous):

In the numerator, all the terms have an "x" so you can factor one out. When you factor out an x, you're decreasing the exponent on the x by 1. So after factoring out and dividing, you'll be left with \[4x^{3-1} + 5x^{2-1} +3x^{1-1}\]

OpenStudy (anonymous):

once you got the equation 4x^2+5x+3, you can solve for x provided whether it is homogenous or not.

OpenStudy (anonymous):

IDK

OpenStudy (anonymous):

She said that I was exempted from that lesson all i had to do was take the test so it wouldnt be marked down as missing

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