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simplify completely 4x3+5x2+3x -------------- x
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just take out one x from each of the top
so you get 4x^2 +5x +3
In the numerator, all the terms have an "x" so you can factor one out. When you factor out an x, you're decreasing the exponent on the x by 1. So after factoring out and dividing, you'll be left with \[4x^{3-1} + 5x^{2-1} +3x^{1-1}\]
once you got the equation 4x^2+5x+3, you can solve for x provided whether it is homogenous or not.
IDK
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She said that I was exempted from that lesson all i had to do was take the test so it wouldnt be marked down as missing
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