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Write the expression as a single natural logarithm. 2 ln x – 4 ln c
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http://www.chilimath.com/algebra/advanced/log/images/rules%20of%20exponents.gif look at Rule 3 there, use that 1st :)
once that's done, use Rule 2 from there :)
I still don't get it
ahemm 2ln(x) \( \bf klog(m) \implies log(m^k)\\ 2ln(x) \implies ln(x^2)\)
Ooooooo now I get it, thanks!
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yw
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