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Mathematics 13 Online
OpenStudy (anonymous):

An object is launched at 25 m/s from a height of 80 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.9t2 + 25t + 80. What is the object's maximum height?

OpenStudy (anonymous):

Never n=mind , I plugged it in it;s 111ft

OpenStudy (anonymous):

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