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6x3/4 in radical form is cubed root of 6x to the fourth right?
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top is exponent, bottom is radical index
is that (6x)^(3/4) or 6 x^(3/4)
its 6x^3/4
as is, the notation suggests that the 6 is just a multiplier to x^3/4
\[6x^\frac{ 3 }{ 4 }\]
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\[\Large kx^{a/b}=k~\sqrt[b]{x^a}~~or~~k~(\sqrt[b]{a~})^a\]
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