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the line tangent of f(x) = 2X\(2X+1) is Y = 2X +1 at point (a,b) Find b
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graph the function and the tangent line and see what the y-value of the tangent point is
The slope of the given tangent line is 2. Find out when \(f'(x)=2\): \[f(x)=\frac{2x}{2x+1}\\ f'(x)=\frac{2}{(2x+1)^2}\] Solve for \(x\) in the following equation: \[\frac{2}{(2x+1)^2}=2\] This \(x\) tells you when the slope of the tangent line to \(f\) is 2.
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