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how do you distribute x^-1/2
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x/1/2=2x
ok how about one step further. \[\frac{ 1 }{ 2 }(5-3x)^{-1/2}\times (-3)\]
can you show me step process?
well i just did it simply =)
whats the answer?
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okay let me show u -- x^-1/2 =x/1/2=x.2/1=2x/1=2x
no I'm asking how I can solve the equation I wrote just now :) thanks about 2x though
1/2.(5-3x)^-1/2.(-3) =1/2(5-3x/1/2).(-3) =1/2.2(5-3x).(-3) =10-6x/2.(-3) =2(5-3x)/2.(-3) =5-3x.(-3) =-15+9x =9x-15 =3(3x-5)
thanks!
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