Having a problem with a word problem: a rectangular garden has dimensions of 25 feet by 13 feet. A gravel path of consistent width is to be built around the garden. How wide can the path be if there is enough gravel for 480 feet?

Question

anonymous · Answer

let x =width of the gravel path

Draw rough diagram of this labeling the garden as 25 by 13and the width of the gravel path as x
You will see the overall dimensions will be (2x+25) by (2x+13)
 Overall area - garden area = gravel path area (required to be  480 feet
(2x+25)(2x+13)-25.13=480
4x^2+26x+50x+325-325=480
4x^2+26x-480=0
Simplify, divide equation by 2:
2x^2+13x-240=0

anonymous · Answer

middle term the equation

anonymous · Answer

That is where I end up getting stuck..divide all by 2 then factor?