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Find the area of a regular hexagon with radius 12 in. Round to the nearest whole number.
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A = \[\frac{ 3\sqrt{3}*r^2 }{ 2 }\]
where r is the radius
Thank you both! Appreciate it =] @blurbendy @ybarrap
Regular hexagons have 6 equilateral triangles, each with height (h) equal to it's apothem: h = apothem = sqrt(r^2 - (r/2)^2) A = 6 * (1/2) base * h = 6 * (1/2) * r * r * sqrt(3)/2 = 3*sqrt(3)*r^2/2 where r is radius (12 in).
yw :)
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