Question

k

Answer 1

\[\cos \theta =\frac{ 4 }{ \sqrt{4^2+(-\sqrt{33})^2 }}=\frac{ 4 }{ 7 }\]

Answer 2

cos θ = 7/4

cos θ = square root of 33/4

cos θ = 4/7

cos θ = square root of 33/7