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9^2x=66
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Have you worked with logarithms before?
that's what im doing right now.. I have to solve it by using logarithms. its hard though
So you have the following equation: \[9^{2x}=66\]You'll start by taking the natural log of both sides. When we take the natural log of the left side, the 2x drops down in front like this: \[2x \ln 9 = \ln 66\]Now we just need to isolate x. We start by dividing both sides by ln 9: \[2x=\ln 66 / \ln 9\]Now, just divide both sides by 2, and we're done.
I got 1.7012 and its wrong :/
\[\ln 66 / \ln 9 \approx 1.907\]Now, just divide this by two to get your answer.
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