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OpenStudy (anonymous):
if (a/x)-(b/y)=c and xy=1/c, then bx= (a)1-ay (b)ay (c)ay+1 (d)ay-1 (e)2ay
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OpenStudy (anonymous):
\[\frac{ a }{ x }-\frac{ b }{ y }=c,xy=\frac{ 1 }{ c }\] \[\frac{ ay-bx}{ xy }=c\] \[ay-bx=cxy=c \frac{ 1 }{ c }=1\] bx=ay-1
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