Question

If c & d= c^2+ d^2-4, then 2 & 1=
a.-2
b.-1
c.0
d.1
e.2

Answer 1

If c & d= c^2+ d^2-4, then 2 & 1 that means c=2 and d=1 since c & d and 2 & 1 are in a same form. so just substitute 2 into the place of c and 1 into the place of d

then it becomes: 2^2+1^2-4=4+2-4=2

Answer 2

thank you

Answer 3

\[2 and 1=2^{2}+1^{2}-4=4+1-4=1\]

Answer 4

oh yeah oppps mistake lol

Answer 5

Sorry for that, made a calculation mistake D: