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Precalculus
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OpenStudy (anonymous):
How do I solve (d+1/2)^2=1
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OpenStudy (blurbendy):
d + / 2 ???
OpenStudy (blurbendy):
oh d + 1 all over 2?
OpenStudy (anonymous):
if \((d+\frac{1}{2})^2=1\) then \(d+\frac{1}{2}=1\) or \(d+\frac{1}{2}=-1\)
OpenStudy (anonymous):
Im trying to find the roots by factoring
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