Question

Write an algebraic equation for the following.

A number added to itself six additional times is four less than the number squared.
A. x^7=x^2-4
B. 7x=4-x^2
C. 7x= x^2-4
D. 6x=x^2-4

Answer 1

I think it's D because it's the only one with the number 6 in its equation

Answer 2

yea that would be it cuz it is x+x+x+x+x+x=x*x-4=6x=x^2-4

Answer 3

thanks(: