Question

if f(x)=cosx and g(x)=9^x, what is the range of g(f(x))?

Answer 1

\[\large g(f(x))=9^{\cos x}\]
\(\cos x\) is bounded between 1 and -1, which means \(f(g(x))\) is bounded between \(9^1\) and \(9^{-1}\).

Answer 2

\(9^{-1} = \cfrac{1}{9}\)

Answer 3

\[\large \cfrac{1}{9} \le 9^{cos(x)} \le 9\]

Answer 4

OOOOH !....

Answer 5

:)

Answer 6

thanks..

Answer 7

:)

Answer 8

No problemo