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if f(x) = sec x and g(x)= sin x , which statement is true, a) (f×g)(x)= cosx b) (f×g)(x)= cotx c) (f×g)(x)= cscx d) (f×g)(x)= tanx
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\[(f×g)(x)=f(x)g(x)=\]
simplify using \[\sec=\frac1\cos\]
OH WAIT.... got it ..
sec x = 1/cosx 1/cosx (sinx) = sinx/cosx = tan x
Nice ^_^
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Excellent work @alexeis_nicole \[\boxed{\huge\color{red}\checkmark}\]
thanks! sorry if i didn't get that quicker than i should have... haven't stopped studying since yesterday morning. i know i should put this down but im actually terrified to
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