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solve the equation below for x. 4^x=5.6962
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round to 2 decimal places
I got 1.25? or 1.26 I think
take the logarithm of base 4 to both side of the equation
yeah that's how I got my answer
1.25 ?
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Yep
\[b^x=A\iff x=\frac{\ln(A)}{\ln(b)}\]
yes, I just wanted to make sure because my teacher wants us to be very specific on rounding, where I got 1.25 and then 1.26
so I wasn't sure :p
\[4^x=5.6962\\ x=\log_4(5.6962)=\frac{\ln(5.6962)}{\ln(4)}=1.254999900921=1.25 (\text{2dps})\]
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thank u both :)
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