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Find the equation of the circle whose center and radius are given. center (0, 8), radius = 8
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hint: (x-h)^2+(y-k)^2=r^2 is the general equation of a circle where (h,k) is the center r is the radius
Im confused
what is the center in this case?
(0,8)
so (h,k) = (0,8) which means h = 0 k = 8
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the radius is given to be 8, so r = 8
so whats the answer
plug in h = 0, k = 8 and r = 8 into (x-h)^2+(y-k)^2=r^2 to get your answer
i got it thanks
yw
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