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Simplify: http://curriculum.kcdistancelearning.com/courses/ALG1x-HS-A06/b/Exams/9HW2/9HW2_q3.gif
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Do you know how to factor?
x^2-9/x^2-6x+9 =>x^2-9/x^2-3x-3x+9 =>x^2-9/x(x-3)-3(x-3) =>(x+3)(x-3)/(x-3)(x-3) =>x+3/x-3
@Muffinator no
Ok, it is a bit tricky at first.
The top of your problem is [x^2-9\].
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\[x^2-9\]
It is the same thing as (x-3) times (x+3)
When you multiply (x-3)(x+3), it becomes \[x^2-9\]
Tell me if you want me to go on :/
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