Question

gae

Answer 1

find the derivative
f' = -sinx - cosx = 0 for max/min
-sinx = cosx
-tanx = 1
tanx = -1

can you solve this for x?

Answer 2

I already had that, but I appreciate the input. I figured it out.

Answer 3

sqrt(2) cosx/sqrt(2)-sinx/sqrt(2)=sqrt(2)*( cosx cos pi/4 -sinx sin pi/4)
=sqrt(2) * cos(x+pi/4)
use -1<=cos(theta)<=1

Answer 4

the max and min values of the function will be sqty2 and -sqrt2