Question

The vertex of the parabola below is at the point(1,-3). what is the equation?

Answer 1

if memory serves me this morning
\[V_x=-\frac{b}{2a}\]\[V_y=c+\frac{b^2}{4a}\]

Answer 2

\[y=a\frac{b^2}{4a^2}+b\frac{-b}{2a}+c\]
\[y=\frac{b^2}{4a}-\frac{b^2}{2a}+c\]
\[y=\frac{b^2-2b^2}{4a}+c\]
\[y=\frac{-b^2}{4a}+c\]
\[y=c-\frac{b^2}{4a}\]
looks better