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help please!:) Expand the series and evaluate: Enter your answer as the example: 1+2+3+4+5=15
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\[\sum_{k=1}^{5} [8(k+1)]\]
16+24+32+40+48=160
\[\sum_{k=1}^{5}\left[ 8\left( k+1 \right) \right]\] =8(1+1)+8(2+1)+8(3+1)+8(4+1)+8(5+1) =8(2+3+4+5+6) =8*20=160
thanks guys!:)
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